If x=1,y=2 is a solution of equation a^2 x +ay =3,then find the value of a
The given equation is
a2 x + ay = 3
Since x = 1; y = 2 is a solution of the above equation so it must satisfy it.
Put x = 1 and y = 2 in the above equation we get
a2 + 2a = 3
⇒ a2 + 2a - 3 = 0
⇒ a2 + 3a - a - 3 = 0
⇒ a (a + 3) - 1(a + 3) = 0
⇒ (a - 1) (a + 3) = 0
⇒ a - 1 = 0 or a + 3 = 0
⇒ a = 1 or a = -3