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Question

If x=1 , z=2 then,
x2+3xz+2x2+xz=

A
11
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B
10
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C
6
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Solution

The correct option is A 11
Since, x=1 , z=2
So,
x2+3xz+2x2+xz=(x2+2x2)+(3xz+xz)
=3x2+4xz
Now,
3x2+4xz=3(1)2+4×1×2
=11


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