If x-10-0 - 0-1 and y-10-0 - 0-1- then 2x-2y is equal to

The correct option is D Zero Apply formula #10; #10; (A±Δ A) (B±Δ B)=(A B)± (Δ A Δ #10;B) #10; #10;Similarly #10; #10; #160; 2x ...

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Standard VII

Mathematics

Integers

If x=10.0 ±...

Question

If $x = 10.0 \pm 0.1$ and $y = 10.0 \pm 0.1$ , then $2 x - 2 y$ is equal to

(0.0 \pm 0.1)

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Z e r o

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(0.0 \pm 0.4)

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(20 \pm 0.2)

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Solution

The correct option is D $Z e r o$
Apply formula

$(A \pm Δ A) - (B \pm Δ B) = (A - B) \pm (Δ A - Δ B)$

Similarly

$2 x - 2 y = 2 (10.0 \pm 0.1) - 2 (10 \pm 0.1)$

$= (2 \times 10 - 2 \times 10) \pm (2 \times 0.1 - 2 \times 0.1)$

$= 0$

Hence, $2 x - 2 y = Z E R O$

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If x=10.0±0.1 and y=10.0±0.1, then 2x−2y is equal to

The correct option is D ZeroApply formula (A±ΔA)−(B±ΔB)=(A−B)±(ΔA−ΔB) Similarly 2x−2y=2(10.0±0.1)−2(10±0.1) =(2×10−2×10)±(2×0.1−2×0.1) =0 Hence, 2x−2y=ZERO

If $x = 10.0 \pm 0.1$ and $y = 10.0 \pm 0.1$ , then $2 x - 2 y$ is equal to

The correct option is D $Z e r o$
Apply formula

$(A \pm Δ A) - (B \pm Δ B) = (A - B) \pm (Δ A - Δ B)$

Similarly

$2 x - 2 y = 2 (10.0 \pm 0.1) - 2 (10 \pm 0.1)$

$= (2 \times 10 - 2 \times 10) \pm (2 \times 0.1 - 2 \times 0.1)$

$= 0$

Hence, $2 x - 2 y = Z E R O$