The correct option is D R4={(1,3),(2,1)(2,5),(3,7),(7,9)}
We have,
R1={(x,y):y=x+2;x∈X,y∈Y}
={(1,3),(3,5),(5,7)}
so, we can say that, R1,R2,R3 are subsets of X×Y.
In R4, we have (7,9)
but (7,9)∉X×Y, because 7 is not an element of set X. So, R4 is not a subset of X to Y
∴R4 is not a relation from X to Y