Question

If $x^{140}+2x^{151}+k$ is divisible by x + 1, then the value of k is

• A. 1
• B. -3
• C. 2
• D. -2

Answer 1

The correct option is A 1

Given, $x^{140}+2x^{151}+k$ is divisible by x + 1
$\therefore x+1$ is a factor of $x^{140}+2x^{151}+k$
$x+1=0$
$x=-1$
$(-1{)}^{140}+2(-1{)}^{151}+k=0$
$1-2+k=0$
$k=1$
Option A is correct.