If $x = 15^{0}$ , evaluate:
$4 cos 2 x sin 4 x tan 3 x - 1$

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Solution

Given, $x = 15^{\circ}$
Now, $4 cos 2 x sin 4 x tan 3 x - 1$
= $4 (cos 30^{0}) (sin 60^{0}) (tan 45^{0}) - 1$
= $4 (\frac{\sqrt{3}}{2}) (\frac{\sqrt{3}}{2}) (1) - 1$
= $3 - 1$
= $2$

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