If $x = 15^{0}$ , verify that $4 s i n 2 x c o s 4 x s i n 6 x = 1$ .

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Solution

We have,
$x = 15^{0}$

L.H.S
$= 4 sin 2 x cos 4 x sin 6 x$
$= 4 sin 30^{0} cos 60^{0} sin 90^{0}$
$= 4 \times \frac{1}{2} \times \frac{1}{2} \times 1$
$= 1$

Hence, proved.

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