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Expansion of (x+a)(x+b)

If x-1 x=12, ...

Question

If $x - \frac{1}{x} = \frac{1}{2}$ , then write the value of $4 x^{2} + \frac{4}{x^{2}}$

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Solution

We have to find the value of

Given

Using identity

Here

By substituting the value of we get

By transposing – 2 to left hand side we get

By taking least common multiply we get

By multiplying 4 on both sides we get

Hence the value of is

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|\begin{matrix} x + 1 & x - 1 \\ x - 3 & x + 2 \end{matrix}| = |\begin{matrix} 4 & - 1 \\ 1 & 3 \end{matrix}|

, then write the value of x.

If $x - \frac{1}{x} = \frac{1}{2}$ , then write the value of $4 x^{2} + \frac{4}{x^{2}}$ .

[\begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix}] = [\begin{matrix} 4 & - 1 1 & 3 \end{matrix}]

, then write the value of

x

∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 1 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣

, then write the value of

x

\sqrt{2} - 1

, then write the value of

\frac{1}{x} .

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