If $x = 2^{1 / 3} - 2,$ then $x^{3} + 6 x^{2} + 12 x =$ ?

6

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Solution

The correct option is C $- 6$
Given, $x + 2 = 2^{1 / 3}$ .

Cubing both sides,
$⟹ (x + 2)^{3} = 2$
$⟹ x^{3} + 6 x^{2} + 12 x + 8 = 2$
$⟹ x^{3} + 6 x^{2} + 12 x = - 6$ .

Therefore, option $B$ is correct.

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Similar questions

If $x$ = $2 + 2^{\frac{2}{3}} + 2^{\frac{1}{3}}$ , then $x^{3} - 6 x^{2} + 6 x$ =

x = 2 + 2^{\frac{1}{3}} + 2^{\frac{2}{3}}

x^{3} - 6 x^{2} + 6 x =

x = 2 + 2^{1 / 3} + 2^{2 / 3}

x^{3} - 6 x^{2} + 6 x =

x = 2 + 2^{1 / 3} + 2^{2 / 3}

x^{3} - 6 x^{2} + 6 x =

f (x) = x^{3} - 6 x^{2} + 12 x - 3

x = 2, f (x)

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