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Static Friction

If x * 2+1 / ...

Question

If x2+1/x2=27,then value of x+1/x is

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Solution

We know !

(x + 1/x)² = x² + 1/x² + 2

(x + 1/x)² = 27 + 2

(x + 1/x)² = 29

taking square roots on both sides

x + 1/x = √29

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Similar questions

x^{2} + x + 1 = 0

, then the value of

(x + 1 / x)^{2} + (x^{2} + 1 / x^{2})^{2} + . . . . . + (x^{27} + 1 / x^{27})^{2}

x^{2} + x + 1 = 0

, then the value of

{(x + \frac{1}{x})}^{2} + {(x^{2} + \frac{1}{x^{2}})}^{2} + . . . + {(x^{27} + \frac{1}{x^{27}})}^{2}

x^{2} + x + 1 = 0

, then the numerical value of

{(x + \frac{1}{x})}^{2} + {(x^{2} + \frac{1}{x^{2}})}^{2} + {(x^{3} + \frac{1}{x^{3}})}^{2} + {(x^{4} + \frac{1}{x^{4}})}^{2} + . . . . + {(x^{27} + \frac{1}{x^{27}})}^{2}

x^{2} + \frac{1}{x^{2}} = 27

, find the value of

x - \frac{1}{x}

.

If $x^{2} + (\frac{1}{x^{2}}) = 27,$ find the value of $x + (\frac{1}{x}) .$

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