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Question

If x211x+a and x214x+2a have a common factor, then what are the values of a?

A
0,7
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B
5,20
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C
0,24
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D
1,3
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Solution

The correct option is C 0,24
Let (xα) be the common factor then
α211α+a=0&α214α+2a=0
Subtract 2 eqn we get a=3α
α211α+3α=0α(α8)=0
α=0,8a=0,24

1121787_552732_ans_2c48b357967d499a9b3dbddaa40b57e3.jpg

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