CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x=2+22/3+21/3, then the value of x36x2+6x is

A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2
Given:
x=2+22/3+21/3
x2=22/3+21/3,
Cubing the equation on both sides, we get
(x2)3=4+2+3×22/3×21/3(22/3+21/3)
x38+6x(x2)=6+6(x2)
x36x2+12x8=6+6x
x36x2+6x=2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon