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Question

If x22x15=(x+r)(x+s) for all xR, then the possible value(s) of rs is/are

A
3
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B
2
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C
2
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D
8
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Solution

The correct option is D 8
Given, x22x15=(x+r)(x+s)
x22x15=0
On factoring, we get
(x5)(x+3)=0
So the value of r=3,s=5
Therefore, rs=3(5)=8

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