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Question

If x2+2x+3<cos1(cos4)+2cot1(cot5) xZ, then number of integral value(s) of x is

A
0
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B
2
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C
3
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D
4
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Solution

The correct option is C 3
Given:
x2+2x+3<cos1(cos4)+2cot1(cot5)
We know that
cos1(cosx)=2πx ; π<x<2π
cot1(cotx)=xπ ; π<x<2π
Then inequality becomes
x2+2x+3<2π4+2×(5π)
x2+2x3<0
(x+3)(x1)<0
x(3,1)
since xZ
x=2,1,0

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