If x2−2x+log12p=0 does not have two distinct real roots, then the maximum value of p is
A
2
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B
1
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C
14
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D
12
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Solution
The correct option is D12 x2−2x+log12p=0 It does not have two distinct real roots means It can have either equal real roots or imaginary roots. So, D≤0 ⇒4−4log12p≤0⇒4+4log2p≤0⇒log2p≤−1⇒p≤2−1⇒p≤12