If x=(/(2-3^1/2), then the value of (x^3-2x^2-7x+5

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x=(/(2-3^1/2), would you please check it again, its not clear.

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If x=1/(2-√3),then the value of (x^3-2x^2-7x+5)

If $x = \frac{1}{(2 - \sqrt{3}),}$ then find the value of $(x^{3} - 2 x^{2} - 7 x + 5)$ .

x = \frac{1}{2 - \sqrt{3}}

x^{3} + 2 x^{2} - 7 x + 5

x = \frac{1}{2 - \sqrt{3}}

x^{3} - 2 x^{2} - 7 x + 5 = m

m

x = \frac{1}{2 - \sqrt{3}}

x^{3} - 2 x^{2} - 7 x + 5

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