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Question

If x=2+3cosθ and y=13sinθ represent a circle, then the centre and radius is

A
(2,1),9
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B
(2,1),3
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C
(1,2),13
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D
(2,1),3
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Solution

The correct option is B (2,1),3
x=2+3cosθ
(x2)2=(3cosθ)2 (1)
y=13sinθ
(y1)2=(3sinθ)2 (2)
Adding (1) and (2), we get
(x2)2+(y1)2=32

Comparing with (xx0)2+(yy0)2=r2, we get
centre, (x0,y0)=(2,1)
and radius, r=3

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