Question

If $x^2-36=0$, which of the following could be a value of $x$?

• A. $-6$
• B. $-4$
• C. $0$
• D. $3$
• E. $12$

Answer 1

The correct option is A $-6$

Given, $x^2$ $-$ $36$ $=$ $0$

$\Rightarrow x^2$ $-$ $6^2$ $=$ $0$

We know that

$a^2$ $-$ $b^2$ $=$ $(a-b)$$(a+b)$

From above, we can write the given equation as

$(x-6)$$(x+6)$ $=$ $0$

Possible values of ${}^{\prime }{x}^{\prime }$ can be found by equating

$(x-6)$ $=$ $0$ $or$ $(x+6)$ $=$ $0$

$\Rightarrow x$ $=$ $6$ or $x$ $=$ $-6$

Therefore, option A $-6$ is the correct answer.