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Question

If x2āˆ’3x+2 be a factor of x4āˆ’px2+q, then (p, q) =


A

(4, 3)

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B

(4, 5)

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C

(5, 4)

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D

(3, 4)

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Solution

The correct option is C

(5, 4)


x23x+2 be factor of x4px2+q=0

Hence (x23x+2)=0 ⇒ (x-2)(x-1) = 0

⇒ x = 2, 1, putting these values in given equation

so, 4p - q -16 = 0 ......(i)

and, p - q - 1 = 0 .......(ii)

Solving (i) and (ii), we get (p, q) = (5, 4)


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