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Question

If x2āˆ’3x+2 be a factor of x4āˆ’px2+q, then (p,q)=

A
(5,4)
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B
(4,3)
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C
(4,5)
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D
(3,4)
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Solution

The correct option is A (5,4)
x23x+2 be factor of x4px2+q=0

Hence, (x23x+2)=0 (x2)(x1)=0

x=2,1 putting these values in given equation

So, 4pq16=0 ...(i)
And pq1=0 ...(ii)

Solving (i) and (ii), we get (p,q)=(5,4)

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