wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x23x+2 is a factor of x4ax2+b then the equation whose roots are a,b is

A
x29x+20=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+9x20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x29x20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+9x+20=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x29x+20=0
x23x+2=(x1)(x2) is factor of f(x)=x4ax2+b
So,f(1)=0 and f(2)=0
1a+b=0 and 164a+b=0
a=5,b=4
Required equation: x2(5+4)x+5.4=0
x29x+20=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solution of tanθ = tanα
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon