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Question

If x23x+2 is a factor of x4ax2+b then the equation whose roots are a,b is

A
x29x20=0
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B
x29x+20=0
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C
x2+9x+20=0
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D
x2+9x20=0
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Solution

The correct option is B x29x+20=0
x23x+2=(x1)(x2) is factor of f(x)=x4ax2+b
So,f(1)=0 and f(2)=0
1a+b=0 and 164a+b=0
a=5,b=4
Required equation: x2(5+4)x+5.4=0
x29x+20=0

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