If $x^{2} = 4$ , then find the value of $x^{3}$

- 8

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- 4

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2

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6

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12

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Solution

The correct option is A $- 8$
Given,
$x^{2} = 4$
$x = \sqrt{4}$
$x = + 2 o r - 2$
if $x = 2$ then,
$x^{3} = 8$
and if $x = - 2$
$x^{3} = - 8$

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