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Long Division Method to Divide Two Polynomials

If x = 2 + ...

Question

If $x = 2 + 5!,$ then the value of $x^{3} - 5 x^{2} + 33 x - 19$ is

4

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6

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8

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None of these

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Solution

The correct option is C None of these
$x = 2 + 5! = 2 + (5 \times 4 \times 3 \times 2 \times 1) = 122$

$\Rightarrow$ $x^{3} - 5 x^{2} + 33 x - 19$

$=$ ${(122)}^{3} - 5 {(122)}^{2} + 33 (122) - 19$

$=$ $1815848 - 74420 + 4026 - 19$

$=$ $1745435$

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Similar questions

x^{3} - 5 x^{2} + 33 x - 19

x - 2 = 5 i

If x = 2 + 5i and $\frac{2}{9!}$ + $\frac{2}{3! 7!}$ = $\frac{2^{a}}{b!}$ , then $x^{3} - 5 x^{2}$ + 33x - 19 =

x = 2 + i

\frac{1}{0! 8!} + \frac{1}{2! 6!} + \frac{1}{2! 4! 4!} = \frac{2^{a - 1}}{m!}

x^{3} - 5 x^{2} + 9 x + 10

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1 i = \sqrt{- 1})

2 (\frac{1}{1! 9!} + \frac{1}{3! 7!}) + \frac{1}{5! 5!} = \frac{2^{a}}{b!}

x^{3} - 5 x^{2} + 33 x - 10 =

x 4 - x 2 - 2 x + 6

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