The correct option is B xϵ [2,4]
Given:[x]2–5[x]+6=0 … (i)
Let y=[x]
Then equation (i) becomes
y2–5y+6=0
⇒y2–3y–2y+3×2=0
⇒y(y–3)−2(y–3)=0
⇒(y–3)(y−2)=0
⇒y=3ory=2
Since,y=[x]
Therefore,[x]=3or[x]=2⇒xϵ[3,4) or xϵ[2,3)⇒xϵ[2,4)
Hence, the correct option is (D)