If $x^{2} - 725 = 0$ , then find the value of $x$ .

\pm 2 \sqrt{29}

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\pm 5 \sqrt{29}

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\pm 3 \sqrt{29}

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\pm 4 \sqrt{29}

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Solution

The correct option is C $\pm 5 \sqrt{29}$
Given equation is: $x^{2} - 725 = 0$
$x^{2} = 725$
$x^{2} = 25 \times 29$
Taking roots on both the sides, we get
$x = \pm 5 \sqrt{29}$

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If x2−725=0, then find the value of x.

The correct option is C ±5√29Given equation is: x2−725=0x2=725x2=25×29Taking roots on both the sides, we getx=±5√29

If $x^{2} - 725 = 0$ , then find the value of $x$ .

The correct option is C $\pm 5 \sqrt{29}$
Given equation is: $x^{2} - 725 = 0$
$x^{2} = 725$
$x^{2} = 25 \times 29$
Taking roots on both the sides, we get
$x = \pm 5 \sqrt{29}$