You visited us 1 times! Enjoying our articles? Unlock Full Access!

Buoyant Force

If x2-8 x+13 ...

Question

If $x^{2} - 8 x + 13$ can be written as (x – a)(x – 6) + 1. Find the value of a.

__

Open in App

Solution

$x^{2} - 8 x + 13 = (x - a) (x - 6) + 1$
or, $x - a = \frac{x^{2} - 8 x + 12}{x - 6}$

$\begin{matrix} x - 2 x - 6 x^{2} - 8 x + 12 x^{2} - 6 x - ------ - - 2 x + 12 - 2 x + 12 - -------- - 0 \end{matrix}$

Hence, a = 2

Suggest Corrections

Similar questions

x^{2} - 7 x - 98 = 0

(x + a) (x - 2 a) = 0,

‘ a^{'}

x

x^{2} - 8 x + 13 = 0

If (x – p) and (x – q) are the factors of the polynomial P(x) = $x^{2}$ + ax + b =0, then P(x) can be written as:

f (x) = x^{2} + 4 x - 6

f (x)

(x + m)^{2} + n

m

n

p (x)

(a x - b) (a x + b)

1 < a \leq 3

2 < b < 4

a, b

p (x)

Join BYJU'S Learning Program