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Question

If x=2α+1 and y=α1 is a solution of the equation 2x3y+5=0. Find the value of α.

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Solution

Given equation: 2x3y+5=0

Since (2α+1,α1) is the solution of equation 2x3y+5=0, it will satisfy the equation

Substituting x=2α+1 and y=α1 in 2x3y+5=0, we get

2(2α+1)3(α1)+5=0

4α+23α+3+5=0

α+10=0

α=10

Hence, the value of α is 10.

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