If x=2α+1 and y=α−1 is a solution of the equation 2x−3y+5=0, find the value of α.
x=2α+1 and y=α−1 are the solution of the equation 2x−3y+5=0
Substituting the value of x and y
2(2α+1)−3 (α−1)+5=0
⇒ 4α+2−3α+3+5=0
⇒ α+10=0⇒ α=−10
Hence, α=−10
If α is the value of xϵ[0,2π] which is a solution of the equation
2 cos2 x2+x6 = 2x + 2−x, then find the value of 2α3π .