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Question

If (x-2) and (x-1/2) are the factors of the polynomial qx2+5x+p, then find the relation between p and q.


A

p=q

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B

p≠q

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C

p<q

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D

p>q

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Solution

The correct option is A

p=q


Let f(x) = qx2+5x+p
Since x - 2 is a factor therefore f(2) = 0 by factor theorem
q(22) + 5(2) + p = 0
4q + p = - 10 ........(i)

Since x -1/2 is a factor therefore f(1/2) = 0 by factor theorem
q(1/2) 2 + 5(1/2) + p = 0
q/4 + p = - 5/2 .....(ii)

(i) - (ii)
4q –q/4 = - 10 + 5/2
16q - q = - 40 + 10
5 q = - 30
q = - 2
Substituting in (i)
4(- 2) + r = - 10
p = - 10 + 8
p = - 2
Therefore, p = q = -2


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