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Question

If x2−bx+c=0 has equal integral roots, then

A
b and c are integers.
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B
b and c are even integers.
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C
b is an even integer and c is a perfect square of an integer.
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D
none of these.
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Solution

The correct options are
B b is an even integer and c is a perfect square of an integer.
C b and c are integers.
Given equation x2bx+c=0
Let α,α be equal integral roots.
So, α+α=b,α.α=c
b=2α,c=α2.
Since, α is integer, so b is an even integer.
Also, c is perfect square of an integer.

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