Question

If $x^2-\frac{1}{9}=0$,then find value of x:

Answer 1

$x^2-\frac{1}{9}=0$

$x^2-{\left(\frac{1}{3}\right)}^2=0$ is of the form $a^2-b^2=(a-b)(a+b)$

$=(x-\frac{1}{3})(x+\frac{1}{3})=0$

$\therefore x=\frac{1}{3},\frac{-1}{3}$