If x2-1x2-23-find the value of x-1x

As we know that (a+b)^2=a^2+b^2+2 a b (x+1x)^2=x^2+(1x)^2+2(x)(1x)=x^2+1x^2+2=23+2=25 So (x+1x)^2=25 x+1x=√(25) x+1x=± 5 ...

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Expansion of (a ± b)²

If x2+1x2=2...

Question

If $x^{2} + \frac{1}{x^{2}} = 23$ ,find the value of $x + \frac{1}{x}$

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