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Question

If x2+1x2=27, find the value of x1x

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Solution

x1x
We have,
(x1x)2=x22×x×1x+1x2
(x1x)2=x22+1x2
(x1x)2=x2+1x22
(x1x)2=272[x2+1x2=27 given]
(x1x)2=25(x1x)2
x1x=±5
[Taking square root of both sides]

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