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Question

If x2 is a factor of kx22x+1, then find the value of k

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Solution

We have,

x2 is a factor of kx22x+1

Then,

x2=0

x=2

Put in the given equation

k(2)22(2)+1=0

4k22+1=0

4k=221

k=2214

Hence, this is the answer.


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