We have,
x−2 is a factor of kx2−√2x+1
Then,
x−2=0
x=2
Put in the given equation
k(2)2−√2(2)+1=0
4k−2√2+1=0
4k=2√2−1
k=2√2−14
Hence, this is the answer.
find the value of k if (x-1) is a factor of the polynomial kx2-3x+k
Find the value of k, if x - 1 is a factor p(x) in each of the following cases: (i) p(x)=x2+x+k (ii) p(x)=2x2+kx+√2 (iii) p(x)=kx2−√2x+1 (iv) p(x)=kx2−3x+k