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Question

If (x2) is common factor of expressions x2+ax+b and x2+cx+d, then bdca=
(ac)

A
2
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B
2.00
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C
2.0
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Solution

(x2) is a common factor
(x=2) is common root of both the equation
putting the value of x=2 in both the equation
4+2a+b=0 and 4+2c+d=0
On substracting we get
2(ac)+bd=02=bdac=bdca

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