If - x -2- - 9-thenA- x- -7 -11- - x- -7-11- x -11-7-D- x -7 -11- -

The correct option is C xϵ [ 11,7] Given,|x+2|≤ 9 ⇒ 9≤ x+2≤ 9 [∵ |x|≤ a⇒ a≤ x≤ a] ⇒ 9 2≤ x≤ 9 2 ⇒ 11≤ x⩽ 7 ⇒ xϵ [ 11,7] ...

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Inequalities Involving Modulus Function

If | x +2| ≤ ...

Question

If $| x + 2 | \leq 9$ ,then

$x ϵ (- 7, 11)$

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$x ϵ [- 11, 7]$

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$x ϵ (- \infty, - 7) \cup (11, \infty)$

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$x ϵ (- \infty, - 7) \cup [11, \infty)$

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