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Question

If x2+mx+1=0 and (ab)x2+(bc)x+(ca)=0 have both roots common then which of the following is true?

A
m=1
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B
m=2
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C
m=2
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D
b, a, c are in AP
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Solution

The correct options are
B m=2
D b, a, c are in AP
x2+mx+1=0
(ab)x2+(bc)x+(ca)=0
ca=ab
b,a,c are in A.P. b. b+d, b+2d
m=cbab=b+2dbb+db=+2
m=+2

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