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Question

If x=2+3 and xy=1, then x2+x+y2y=?

A
2
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B
3
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C
1
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D
None of these
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Solution

The correct option is A 2
Given, x=2+3.....(1).

And xy=1 then,

y=1x=12+3=23......(2).

Now from (1) we get,

x=12(4+23)=12(3+1)2.

Then, x=12(3+1).

In the same way we can find y=12(31).

Now,

x2+x+y2y

=(3+1)222+3+12+(31)222312

=(3+1)223+3+(31)2233

=(3+1)2×3+(31)2×3

=16×23

=2.

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