wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x=2+3,xy=1, then find x2x+y2y.

A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
43
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2
Given:x=2+3,xy=1 On solving for x2x+y2yx2x+xy2xxy=x2x+12x12+32(2+3)+12(2+3)1(2+3)3+12(2+3)1(2+3)3+13+23=6736+33(3+23) ...(Adding both the fractions)(12+63)3(3+23)6(2+3)3(2+3)=63=2.

flag
Suggest Corrections
thumbs-up
20
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Revisiting Irrational Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon