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Question

If x=2+3,xy=1, then find x2x+y2y.

A
3
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B
23
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C
2
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D
43
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Solution

The correct option is C 2
Given:x=2+3,xy=1 On solving for x2x+y2yx2x+xy2xxy=x2x+12x12+32(2+3)+12(2+3)1(2+3)3+12(2+3)1(2+3)3+13+23=6736+33(3+23) ...(Adding both the fractions)(12+63)3(3+23)6(2+3)3(2+3)=63=2.

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