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General Solution of tan theta = tan alpha

If x = 2(θ + ...

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If x = 2(θ + sinθ) and y = 2(1 – cosθ), then value of dy/dx is

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x = 2 (θ + sin θ)

y = 2 (1 - cos θ)

, then value of

\frac{d y}{d x}

x = sin θ, y = cos θ

\frac{d y}{d x}

x = (cos θ + log tan θ)

y = sin θ

,Find the value of

\frac{d y}{d x}

θ = \frac{π}{4}

\frac{d y}{d x},

x = a (θ + sin θ)

y = a (1 - cos θ)

Q. If x = θcosθ – sinθ and y = θsinθ + cosθ, where 'θ' is a parameter, then

\frac{d y}{d x}

equals

यदि x = θcosθ – sinθ तथा y = θsinθ + cosθ, जहाँ 'θ' एक प्राचल है, तब

\frac{d y}{d x}

का मान है

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General Solution of tan theta = tan alpha

Standard XII Mathematics

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