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Greatest Binomial Coefficients

If x2+x+1=0...

Question

If $x^{2} + x + 1 = 0$ then $x^{3}$

A

1

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B

2

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C

3

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D

none of these

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Solution

The correct option is A 1
$x^{2} + x + 1 = 0$

$1 = - x^{2} - x \dots (1)$

$x^{2} = - x - 1$

$x^{3} = - x^{2} - x$

$x^{3} = 1 \dots (f r o m (1))$

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Similar questions

x^{2} + x + 1 = 0

then what is the value of

{(x^{3} + \frac{1}{x^{3}})}^{3}

x_{1}, x_{2}, x_{3}

be the roots of the equation

x^{3} - x + 1 = 0

, then the value of

(\frac{1 + x_{1}}{1 - x_{1}}) (\frac{1 + x_{2}}{1 - x_{2}}) + (\frac{1 + x_{1}}{1 - x_{1}}) (\frac{1 + x_{3}}{1 - x_{3}}) + (\frac{1 + x_{2}}{1 - x_{2}}) (\frac{1 + x_{3}}{1 - x_{3}})

x^{2} + x + 1 = 0

, then value of

{(x + \frac{1}{x})}^{3} + {(x^{2} + \frac{1}{x^{2}})}^{3} + . . . + {(x^{100} + \frac{1}{x^{100}})}^{3}

x^{3} - x - 4

x^{4} - x^{3} - x^{2} + x + 3

x^{4} + x^{2} - 1

?
If true then enter

1

and if false then enter

0

x^{2} - 4 x - 1 = 0

x^{3} - \frac{1}{x^{3}} =

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