Question

If $x^2+x^2={36}^2,$ then find $x$.

• A. $\pm 18\sqrt{2}$
• B. $\pm 9\sqrt{2}$
• C. $\pm 4\sqrt{2}$
• D. $\pm 2\sqrt{2}$

Answer 1

The correct option is A $\pm 18\sqrt{2}$

Consider the given equation.

$x^2+x^2={36}^2$

$2x^2=1296$

$x^2=648$

$x=\pm \sqrt{648}$

$x=\pm 18\sqrt{2}$

Hence, the value of $x$ is $\pm 18\sqrt{2}$.