Question

If $x=2,y=1$ and $z=-3$ then $x^3+y^3+z^3-3xyz$ is equal to

• A. 6
• B. 0
• C. 2
• D. 8

Answer 1

The correct option is B 0

We have,
$x=2,y=1,z=-3$
Since,
$x^3+y^3+z^3-3xyz$

On putting the values of $x,y,z$, we get

$=2^3+1^3+(-3{)}^3+3(2\left)\right(1\left)\right(-3)$
$\therefore x^3+y^3+z^3-3xyz=0$
Hence, this is the answer.