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Question

If x=2,y=1,z=4; find the value of the following expression x2+y2+z2xyyzzx.

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Solution

For x=2,y=1,z=4
x2+y2+z2xyyzzx=(2)2+(1)2+42(2)(1)(1)(4)2(4)=4+1+16+2+48=19

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