If x2-y2-18 and x-y-3- find the value of 16 x2 y2A- 27B- 81C- 243D- 729

The correct option is D 729 (x^2 y^2) = (x y)(x + y) = 18 (x+y) = 18/3 = 6 ——————–I (x y) = 3 —————————–II Solving equations I and II, we get x = 9/2 a ...

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Standard IX

Mathematics

Laws of Exponents for Real Numbers

If x2-y2=18 a...

Question

If $(x^{2} - y^{2})$ = 18 and (x - y) = 3, find the value of 16 $x^{2} y^{2}$

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243

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729

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Solution

The correct option is D
729

$(x^{2} - y^{2})$ = $(x - y) (x + y) = 18$

$(x + y) = \frac{18}{3} = 6$ --------------------I

$(x - y) = 3$ -----------------------------II

Solving equations I and II, we get $x = \frac{9}{2}$ and $y = \frac{3}{2}$

$16 x^{2} y^{2}$ = $16 \times$ $(\frac{9}{2})^{2}$ $\times$ $(\frac{3}{2})^{2} = 729$

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If (x2−y2) = 18 and (x - y) = 3, find the value of 16x2y2

The correct option is D 729 (x2−y2) = (x−y)(x+y)=18 (x+y)=183=6 --------------------I (x−y)=3 -----------------------------II Solving equations I and II, we get x=92 and y=32 16x2y2 = 16× (92)2 × (32)2=729

If $(x^{2} - y^{2})$ = 18 and (x - y) = 3, find the value of 16 $x^{2} y^{2}$