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Question

If (x2−y2)=18 and (x−y)=3, find the value of x2+y2+2xy.


A

27

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B

81

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C

243

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D

729

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Solution

The correct option is C

243


(x2y2)=(xy)(x+y)=18

(xy)=3
(x+y)=183=6

We know the following is an identity

(x2+y2+2xy)=(x+y)2 = 62=36


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