The correct option is A 2
Since the question contains variables, we can assume any value for x and y.
Let, x = y = 1. Then,
x2+y2+1x2+1y2=1+1+1+1=4=4, which is true as per given equation.
∴ x2+y2=1+1=2.
Hence, option (a) is correct answer.
Alternatively:
x2+y2+1x2+1y2−4=0⇒x2+1x2−2+y2+1y2−2=0⇒(x−1x)2+(y−1y)2=0⇒x−1x=0⇒x2−1=0⇒x=1,−1Similary,y=1,−1∴x2+y2=1+1=2