If (x2+y2+z2)=(xy+yz+zx), what is the value of x3+y3+z3?
3xyz
−3xyz
2xyz
−2xyz
We know that x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx)−−−(1) According to question, (x2+y2+z2)=(xy+yz+zx). ∴ RHS will be zero in equation (1) So,x3+y3+z3=3xyz